Bash coding error

General Linux Question
21

Hi @easyt50,
with your example, with all the information from @Akito and @ 01101111, I tried to make a different script to you.

#!/bin/bash

clear

unset ty

echo "1=mp4, 2=avi, 3=wmv, 4=VOB, 0=exit"

while ! [[ $ty =~ ^[0-4]+$ ]] # loop until the regular expression is true
do
    read -srn 1 ty # -r= use "raw input" -s= do not echo keystrokes -n 1=stop reading after 1 character has been read
    read -srt 0.1 debounce # optional: to avoid visible characters when pressing several keys at the same time
done

case $ty in 
    1)
        mf="mp4";;
    2)
        mf="avi";;
    3)
        mf="wmv";;
    4)
        mf="VOB";;
    0)
        exit 0
esac

printf "Selected number=%s - Chosen option=%s\n" $ty $mf

# put your code here ...

exit 0

Note: Please correct my code, because I’m not a programmer and I don’t even know how to program in bash

3 Likes
22

This is excellent @Tech_JA! I tested it and works w/o any errors.
It looks like not only did you code a loop, but also an array. I will have to study this one.
You were wrong about one thing. Yes, you are a programmer. :grinning:
If your code is not Bash, then what is it?

2 Likes